What are the solutions to the equation (r-5)^2=40 ?

The solutions to the equation (r-5)^2=40 are r=2sqrt(10)+5,r=-2sqrt(10)+5

Find the zeros of (r-5)^2=40

The zeros of (r-5)^2=40 are r=2sqrt(10)+5,r=-2sqrt(10)+5

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(r - 5)^{2} = 40

r = 210 + 5, r = - 210 + 5

Decimal Notation

r = 11.32455 \dots, r = - 1.32455 \dots

Solution steps

(r - 5)^{2} = 40

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

r - 5 = 40 : r = 210 + 5

Solve

r - 5 = - 40 : r = - 210 + 5

The solutions to the quadratic equation are:

r = 210 + 5, r = - 210 + 5

2 x^{2} - x - 10 = 0

2 x^{2} + 7 x + 6 = 0

x^{2} + 3 x + 30 = 0

(x - 7) (5 x + 8) = 0

- \frac{1}{500} (x - 100)^{2} + 20 = 0

What are the solutions to the equation (r-5)^2=40 ?
The solutions to the equation (r-5)^2=40 are r=2sqrt(10)+5,r=-2sqrt(10)+5
Find the zeros of (r-5)^2=40
The zeros of (r-5)^2=40 are r=2sqrt(10)+5,r=-2sqrt(10)+5