What are the solutions to the equation x^2-3x+2=2x-3 ?

The solutions to the equation x^2-3x+2=2x-3 are x=(5+sqrt(5))/2 ,x=(5-sqrt(5))/2

Find the zeros of x^2-3x+2=2x-3

The zeros of x^2-3x+2=2x-3 are x=(5+sqrt(5))/2 ,x=(5-sqrt(5))/2

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x^{2} - 3 x + 2 = 2 x - 3

x = \frac{5 + 5}{2}, x = \frac{5 - 5}{2}

Solution steps

x^{2} - 3 x + 2 = 2 x - 3

Move

3

to the left side

x^{2} - 3 x + 5 = 2 x

Move

2 x

to the left side

x^{2} - 5 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 5 = 5

x_{1, 2} = \frac{- ( - 5 ) \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 5}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 5}{2 \cdot 1}

x = \frac{- ( - 5 ) + 5}{2 \cdot 1} : \frac{5 + 5}{2}

x = \frac{- ( - 5 ) - 5}{2 \cdot 1} : \frac{5 - 5}{2}

The solutions to the quadratic equation are:

x = \frac{5 + 5}{2}, x = \frac{5 - 5}{2}

5 x^{2} + 7 x = 5

11 + w^{2} = 2

x, x y - x^{2} = 4 y + x

x^{2} + 3 x - 2 = 0

\frac{3}{2} x^{2} - 6 x + 5 = 0

What are the solutions to the equation x^2-3x+2=2x-3 ?
The solutions to the equation x^2-3x+2=2x-3 are x=(5+sqrt(5))/2 ,x=(5-sqrt(5))/2
Find the zeros of x^2-3x+2=2x-3
The zeros of x^2-3x+2=2x-3 are x=(5+sqrt(5))/2 ,x=(5-sqrt(5))/2