What are the solutions to the equation 5x^2+7x=5 ?

The solutions to the equation 5x^2+7x=5 are x=(-7+sqrt(149))/(10),x=(-7-sqrt(149))/(10)

Find the zeros of 5x^2+7x=5

The zeros of 5x^2+7x=5 are x=(-7+sqrt(149))/(10),x=(-7-sqrt(149))/(10)

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5 x^{2} + 7 x = 5

x = \frac{- 7 + 149}{10}, x = \frac{- 7 - 149}{10}

Solution steps

5 x^{2} + 7 x = 5

Move

5

to the left side

5 x^{2} + 7 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 5 ( - 5 )}{2 \cdot 5}

7^{2} - 4 \cdot 5 (- 5) = 149

x_{1, 2} = \frac{- 7 \pm 149}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 7 + 149}{2 \cdot 5}, x_{2} = \frac{- 7 - 149}{2 \cdot 5}

x = \frac{- 7 + 149}{2 \cdot 5} : \frac{- 7 + 149}{10}

x = \frac{- 7 - 149}{2 \cdot 5} : \frac{- 7 - 149}{10}

The solutions to the quadratic equation are:

x = \frac{- 7 + 149}{10}, x = \frac{- 7 - 149}{10}

11 + w^{2} = 2

x, x y - x^{2} = 4 y + x

x^{2} + 3 x - 2 = 0

\frac{3}{2} x^{2} - 6 x + 5 = 0

x^{2} + 103 = - 18 x + 13

What are the solutions to the equation 5x^2+7x=5 ?
The solutions to the equation 5x^2+7x=5 are x=(-7+sqrt(149))/(10),x=(-7-sqrt(149))/(10)
Find the zeros of 5x^2+7x=5
The zeros of 5x^2+7x=5 are x=(-7+sqrt(149))/(10),x=(-7-sqrt(149))/(10)