What are the solutions to the equation 6x^2+5x-10=0 ?

The solutions to the equation 6x^2+5x-10=0 are x=(-5+sqrt(265))/(12),x=(-5-sqrt(265))/(12)

Find the zeros of 6x^2+5x-10=0

The zeros of 6x^2+5x-10=0 are x=(-5+sqrt(265))/(12),x=(-5-sqrt(265))/(12)

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6 x^{2} + 5 x - 10 = 0

x = \frac{- 5 + 265}{12}, x = \frac{- 5 - 265}{12}

Solution steps

6 x^{2} + 5 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 6 ( - 10 )}{2 \cdot 6}

5^{2} - 4 \cdot 6 (- 10) = 265

x_{1, 2} = \frac{- 5 \pm 265}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 5 + 265}{2 \cdot 6}, x_{2} = \frac{- 5 - 265}{2 \cdot 6}

x = \frac{- 5 + 265}{2 \cdot 6} : \frac{- 5 + 265}{12}

x = \frac{- 5 - 265}{2 \cdot 6} : \frac{- 5 - 265}{12}

The solutions to the quadratic equation are:

x = \frac{- 5 + 265}{12}, x = \frac{- 5 - 265}{12}

- 11 + 6 x^{2} - 4 x^{2} = 0

- x^{2} + 6 x + 2

12 = x^{2} - x

a, p (a - 4) = (a - 4)^{2} - 5

x, x^{2} + 8 x + 1 = 0

What are the solutions to the equation 6x^2+5x-10=0 ?
The solutions to the equation 6x^2+5x-10=0 are x=(-5+sqrt(265))/(12),x=(-5-sqrt(265))/(12)
Find the zeros of 6x^2+5x-10=0
The zeros of 6x^2+5x-10=0 are x=(-5+sqrt(265))/(12),x=(-5-sqrt(265))/(12)