What are the solutions to the equation 49x^2+70x+25=0 ?

The solutions to the equation 49x^2+70x+25=0 are x=-5/7

Find the zeros of 49x^2+70x+25=0

The zeros of 49x^2+70x+25=0 are x=-5/7

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49 x^{2} + 70 x + 25 = 0

x = - \frac{5}{7}

Decimal Notation

x = - 0.71428 \dots

Solution steps

49 x^{2} + 70 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 70 \pm 7 0 ^{2} - 4 \cdot 49 \cdot 25}{2 \cdot 49}

7 0^{2} - 4 \cdot 49 \cdot 25 = 0

x_{1, 2} = \frac{- 70 \pm 0}{2 \cdot 49}

x = \frac{- 70}{2 \cdot 49}

\frac{- 70}{2 \cdot 49} = - \frac{5}{7}

x = - \frac{5}{7}

The solution to the quadratic equation is:

x = - \frac{5}{7}

a^{2} + 3 a + 2 = 0

a x^{2} + b x + c = (5 x - 6) (2 x - 1)

3 x^{2} + 3 x + 8 = 0

5 x^{2} + 8 x - 2 = 0

x^{2} - 2 x = 8 (x - 3)

What are the solutions to the equation 49x^2+70x+25=0 ?
The solutions to the equation 49x^2+70x+25=0 are x=-5/7
Find the zeros of 49x^2+70x+25=0
The zeros of 49x^2+70x+25=0 are x=-5/7