What are the solutions to the equation 5x^2+8x-2=0 ?

The solutions to the equation 5x^2+8x-2=0 are x=(-4+sqrt(26))/5 ,x=-(4+sqrt(26))/5

Find the zeros of 5x^2+8x-2=0

The zeros of 5x^2+8x-2=0 are x=(-4+sqrt(26))/5 ,x=-(4+sqrt(26))/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5 x^{2} + 8 x - 2 = 0

x = \frac{- 4 + 26}{5}, x = - \frac{4 + 26}{5}

Solution steps

5 x^{2} + 8 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 5 ( - 2 )}{2 \cdot 5}

8^{2} - 4 \cdot 5 (- 2) = 226

x_{1, 2} = \frac{- 8 \pm 2 26}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 8 + 2 26}{2 \cdot 5}, x_{2} = \frac{- 8 - 2 26}{2 \cdot 5}

x = \frac{- 8 + 2 26}{2 \cdot 5} : \frac{- 4 + 26}{5}

x = \frac{- 8 - 2 26}{2 \cdot 5} : - \frac{4 + 26}{5}

The solutions to the quadratic equation are:

x = \frac{- 4 + 26}{5}, x = - \frac{4 + 26}{5}

x^{2} - 2 x = 8 (x - 3)

16 (4 - 3 m) = 96 (- m^{2} + 1)

(5 x - 3) (x + 6) = 0

5 w^{2} + 13 w = - 15

x (5 x - 29) = 42

What are the solutions to the equation 5x^2+8x-2=0 ?
The solutions to the equation 5x^2+8x-2=0 are x=(-4+sqrt(26))/5 ,x=-(4+sqrt(26))/5
Find the zeros of 5x^2+8x-2=0
The zeros of 5x^2+8x-2=0 are x=(-4+sqrt(26))/5 ,x=-(4+sqrt(26))/5