What are the solutions to the equation 0=-16x^2+16x+32 ?

The solutions to the equation 0=-16x^2+16x+32 are x=-1,x=2

Find the zeros of 0=-16x^2+16x+32

The zeros of 0=-16x^2+16x+32 are x=-1,x=2

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0 = - 16 x^{2} + 16 x + 32

x = - 1, x = 2

Solution steps

0 = - 16 x^{2} + 16 x + 32

Switch sides

- 16 x^{2} + 16 x + 32 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 ( - 16 ) \cdot 32}{2 ( - 16 )}

1 6^{2} - 4 (- 16) \cdot 32 = 48

x_{1, 2} = \frac{- 16 \pm 48}{2 ( - 16 )}

Separate the solutions

x_{1} = \frac{- 16 + 48}{2 ( - 16 )}, x_{2} = \frac{- 16 - 48}{2 ( - 16 )}

x = \frac{- 16 + 48}{2 ( - 16 )} : - 1

x = \frac{- 16 - 48}{2 ( - 16 )} : 2

The solutions to the quadratic equation are:

x = - 1, x = 2

p^{2} - p - 56 = 0

r^{2} = 10 - 3 r

2 (x + 5)^{2} = 90

3 v^{2} = 7 v + 6

y^{2} - 7.8 y = - 12.65

What are the solutions to the equation 0=-16x^2+16x+32 ?
The solutions to the equation 0=-16x^2+16x+32 are x=-1,x=2
Find the zeros of 0=-16x^2+16x+32
The zeros of 0=-16x^2+16x+32 are x=-1,x=2