What are the solutions to the equation 3v^2=7v+6 ?

The solutions to the equation 3v^2=7v+6 are v=3,v=-2/3

Find the zeros of 3v^2=7v+6

The zeros of 3v^2=7v+6 are v=3,v=-2/3

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3 v^{2} = 7 v + 6

v = 3, v = - \frac{2}{3}

Solution steps

3 v^{2} = 7 v + 6

Move

6

to the left side

3 v^{2} - 6 = 7 v

Move

7 v

to the left side

3 v^{2} - 6 - 7 v = 0

Write in the standard form

a x^{2} + b x + c = 0

3 v^{2} - 7 v - 6 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 3 ( - 6 )}{2 \cdot 3}

(- 7)^{2} - 4 \cdot 3 (- 6) = 11

v_{1, 2} = \frac{- ( - 7 ) \pm 11}{2 \cdot 3}

Separate the solutions

v_{1} = \frac{- ( - 7 ) + 11}{2 \cdot 3}, v_{2} = \frac{- ( - 7 ) - 11}{2 \cdot 3}

v = \frac{- ( - 7 ) + 11}{2 \cdot 3} : 3

v = \frac{- ( - 7 ) - 11}{2 \cdot 3} : - \frac{2}{3}

The solutions to the quadratic equation are:

v = 3, v = - \frac{2}{3}

y^{2} - 7.8 y = - 12.65

x^{2} - 4 x - 10

C = (2 x - 3) (2 x - 2) - 2 x (x - 5)

25 x^{2} + 64 = 0

3 x (x - 1) = 5 - 3 x

What are the solutions to the equation 3v^2=7v+6 ?
The solutions to the equation 3v^2=7v+6 are v=3,v=-2/3
Find the zeros of 3v^2=7v+6
The zeros of 3v^2=7v+6 are v=3,v=-2/3