What are the solutions to the equation C=(2x-3)(2x-2)-2x(x-5) ?

The solutions to the equation C=(2x-3)(2x-2)-2x(x-5) are x=sqrt((C-6)/2),x=-sqrt((C-6)/2)

Find the zeros of C=(2x-3)(2x-2)-2x(x-5)

The zeros of C=(2x-3)(2x-2)-2x(x-5) are x=sqrt((C-6)/2),x=-sqrt((C-6)/2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

C = (2 x - 3) (2 x - 2) - 2 x (x - 5)

x = \frac{C - 6}{2}, x = - \frac{C - 6}{2}

Solution steps

C = (2 x - 3) (2 x - 2) - 2 x (x - 5)

Expand

(2 x - 3) (2 x - 2) - 2 x (x - 5) : 2 x^{2} + 6

C = 2 x^{2} + 6

Switch sides

2 x^{2} + 6 = C

Move

C

to the left side

2 x^{2} + 6 - C = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 2 ( 6 - C )}{2 \cdot 2}

Simplify

0^{2} - 4 \cdot 2 (6 - C) : 22 C - 6

x_{1, 2} = \frac{- 0 \pm 2 2 C - 6}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 0 + 2 2 C - 6}{2 \cdot 2}, x_{2} = \frac{- 0 - 2 2 C - 6}{2 \cdot 2}

x = \frac{- 0 + 2 2 C - 6}{2 \cdot 2} : \frac{C - 6}{2}

x = \frac{- 0 - 2 2 C - 6}{2 \cdot 2} : - \frac{C - 6}{2}

The solutions to the quadratic equation are:

x = \frac{C - 6}{2}, x = - \frac{C - 6}{2}

25 x^{2} + 64 = 0

3 x (x - 1) = 5 - 3 x

a, f (a + 1) = 2 (a + 1)^{2} - 3

3 x^{2} - 324 = 0

x^{2} - 24 x + 36 = 0

What are the solutions to the equation C=(2x-3)(2x-2)-2x(x-5) ?
The solutions to the equation C=(2x-3)(2x-2)-2x(x-5) are x=sqrt((C-6)/2),x=-sqrt((C-6)/2)
Find the zeros of C=(2x-3)(2x-2)-2x(x-5)
The zeros of C=(2x-3)(2x-2)-2x(x-5) are x=sqrt((C-6)/2),x=-sqrt((C-6)/2)