What are the solutions to the equation (x-2)(x-3)=30 ?

The solutions to the equation (x-2)(x-3)=30 are x=8,x=-3

Find the zeros of (x-2)(x-3)=30

The zeros of (x-2)(x-3)=30 are x=8,x=-3

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(x - 2) (x - 3) = 30

x = 8, x = - 3

Solution steps

(x - 2) (x - 3) = 30

Expand

(x - 2) (x - 3) : x^{2} - 5 x + 6

x^{2} - 5 x + 6 = 30

Move

30

to the left side

x^{2} - 5 x - 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 24 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 24) = 11

x_{1, 2} = \frac{- ( - 5 ) \pm 11}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 11}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 11}{2 \cdot 1}

x = \frac{- ( - 5 ) + 11}{2 \cdot 1} : 8

x = \frac{- ( - 5 ) - 11}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = 8, x = - 3

y^{2} = 9 y

7 x + 2 (- 9 x + 3) = x - (- 4 x + 6) x - (- 4 x + 6)

x, x^{2} + 2 x y + y^{2} = 64

x^{2} + 5 = 5 \frac{1}{16}

x^{2} + \frac{x}{2} + 1 = 0

What are the solutions to the equation (x-2)(x-3)=30 ?
The solutions to the equation (x-2)(x-3)=30 are x=8,x=-3
Find the zeros of (x-2)(x-3)=30
The zeros of (x-2)(x-3)=30 are x=8,x=-3