What are the solutions to the equation 7x^2-15x+8=0 ?

The solutions to the equation 7x^2-15x+8=0 are x= 8/7 ,x=1

Find the zeros of 7x^2-15x+8=0

The zeros of 7x^2-15x+8=0 are x= 8/7 ,x=1

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7 x^{2} - 15 x + 8 = 0

x = \frac{8}{7}, x = 1

Decimal Notation

x = 1.14285 \dots, x = 1

Solution steps

7 x^{2} - 15 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 7 \cdot 8}{2 \cdot 7}

(- 15)^{2} - 4 \cdot 7 \cdot 8 = 1

x_{1, 2} = \frac{- ( - 15 ) \pm 1}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 15 ) + 1}{2 \cdot 7}, x_{2} = \frac{- ( - 15 ) - 1}{2 \cdot 7}

x = \frac{- ( - 15 ) + 1}{2 \cdot 7} : \frac{8}{7}

x = \frac{- ( - 15 ) - 1}{2 \cdot 7} : 1

The solutions to the quadratic equation are:

x = \frac{8}{7}, x = 1

2 t (t + 1) = 7

r, y = 4 π r^{2}

x^{2} - 3 \cdot (- 10) = 0

v, F = \frac{d M v ^{2}}{r}

2 (y^{2} + 3 y) = 9

What are the solutions to the equation 7x^2-15x+8=0 ?
The solutions to the equation 7x^2-15x+8=0 are x= 8/7 ,x=1
Find the zeros of 7x^2-15x+8=0
The zeros of 7x^2-15x+8=0 are x= 8/7 ,x=1