What are the solutions to the equation completesquare x^2+4x=5 ?

The solutions to the equation completesquare x^2+4x=5 are x=1,x=-5

Find the zeros of completesquare x^2+4x=5

The zeros of completesquare x^2+4x=5 are x=1,x=-5

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x^{2} + 4 x = 5

x = 1, x = - 5

Solution steps

x^{2} + 4 x = 5

Rewrite in the form

(x + a)^{2} = b

(x + 2)^{2} = 9

For

the solutions are

f (x) = a, - a

Solve

x + 2 = 9 : x = 1

Solve

x + 2 = - 9 : x = - 5

The solutions to the quadratic equation are:

x = 1, x = - 5

2 x^{2} + 7 = 31

(2 x + 4) (x - 2) = (x + 4) (x + 2)

(2 x - 1)^{2} - 225 = 0

3 x^{2} - 4 x = 3

x^{2} + 4 = 6 x - 5

What are the solutions to the equation completesquare x^2+4x=5 ?
The solutions to the equation completesquare x^2+4x=5 are x=1,x=-5
Find the zeros of completesquare x^2+4x=5
The zeros of completesquare x^2+4x=5 are x=1,x=-5