What are the solutions to the equation (3x-2)^2+16=0 ?

The solutions to the equation (3x-2)^2+16=0 are x= 2/3+i 4/3 ,x= 2/3-i 4/3

Find the zeros of (3x-2)^2+16=0

The zeros of (3x-2)^2+16=0 are x= 2/3+i 4/3 ,x= 2/3-i 4/3

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(3 x - 2)^{2} + 16 = 0

x = \frac{2}{3} + i \frac{4}{3}, x = \frac{2}{3} - i \frac{4}{3}

Solution steps

(3 x - 2)^{2} + 16 = 0

Move

16

to the right side

(3 x - 2)^{2} = - 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x - 2 = - 16 : x = \frac{2}{3} + i \frac{4}{3}

Solve

3 x - 2 = - - 16 : x = \frac{2}{3} - i \frac{4}{3}

The solutions to the quadratic equation are:

x = \frac{2}{3} + i \frac{4}{3}, x = \frac{2}{3} - i \frac{4}{3}

4 (x - 100)^{2} = 16

n (n + 1) + 3 = 45

6 x^{2} + 3 = - 2 x

8 x^{2} - 4 x + 6 = 0

4 x^{2} + 12 x - 27 = 13

What are the solutions to the equation (3x-2)^2+16=0 ?
The solutions to the equation (3x-2)^2+16=0 are x= 2/3+i 4/3 ,x= 2/3-i 4/3
Find the zeros of (3x-2)^2+16=0
The zeros of (3x-2)^2+16=0 are x= 2/3+i 4/3 ,x= 2/3-i 4/3