What are the solutions to the equation 8x^2-4x+6=0 ?

The solutions to the equation 8x^2-4x+6=0 are x= 1/4+i(sqrt(11))/4 ,x= 1/4-i(sqrt(11))/4

Find the zeros of 8x^2-4x+6=0

The zeros of 8x^2-4x+6=0 are x= 1/4+i(sqrt(11))/4 ,x= 1/4-i(sqrt(11))/4

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8 x^{2} - 4 x + 6 = 0

x = \frac{1}{4} + i \frac{11}{4}, x = \frac{1}{4} - i \frac{11}{4}

Solution steps

8 x^{2} - 4 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 8 \cdot 6}{2 \cdot 8}

Simplify

(- 4)^{2} - 4 \cdot 8 \cdot 6 : 411 i

x_{1, 2} = \frac{- ( - 4 ) \pm 4 11 i}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4 11 i}{2 \cdot 8}, x_{2} = \frac{- ( - 4 ) - 4 11 i}{2 \cdot 8}

x = \frac{- ( - 4 ) + 4 11 i}{2 \cdot 8} : \frac{1}{4} + i \frac{11}{4}

x = \frac{- ( - 4 ) - 4 11 i}{2 \cdot 8} : \frac{1}{4} - i \frac{11}{4}

The solutions to the quadratic equation are:

x = \frac{1}{4} + i \frac{11}{4}, x = \frac{1}{4} - i \frac{11}{4}

4 x^{2} + 12 x - 27 = 13

z^{2} + 24 z + 140 = 0

98 x^{2} - 2 = 0

6 x^{2} + 2 = 34

\frac{( x + 4 ) ( x - 2 )}{4} = 10

What are the solutions to the equation 8x^2-4x+6=0 ?
The solutions to the equation 8x^2-4x+6=0 are x= 1/4+i(sqrt(11))/4 ,x= 1/4-i(sqrt(11))/4
Find the zeros of 8x^2-4x+6=0
The zeros of 8x^2-4x+6=0 are x= 1/4+i(sqrt(11))/4 ,x= 1/4-i(sqrt(11))/4