What are the solutions to the equation 10x^2=23x+5 ?

The solutions to the equation 10x^2=23x+5 are x= 5/2 ,x=-1/5

Find the zeros of 10x^2=23x+5

The zeros of 10x^2=23x+5 are x= 5/2 ,x=-1/5

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10 x^{2} = 23 x + 5

x = \frac{5}{2}, x = - \frac{1}{5}

Solution steps

10 x^{2} = 23 x + 5

Move

5

to the left side

10 x^{2} - 5 = 23 x

Move

23 x

to the left side

10 x^{2} - 5 - 23 x = 0

Write in the standard form

a x^{2} + b x + c = 0

10 x^{2} - 23 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 23 ) \pm ( - 23 ) ^{2} - 4 \cdot 10 ( - 5 )}{2 \cdot 10}

(- 23)^{2} - 4 \cdot 10 (- 5) = 27

x_{1, 2} = \frac{- ( - 23 ) \pm 27}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- ( - 23 ) + 27}{2 \cdot 10}, x_{2} = \frac{- ( - 23 ) - 27}{2 \cdot 10}

x = \frac{- ( - 23 ) + 27}{2 \cdot 10} : \frac{5}{2}

x = \frac{- ( - 23 ) - 27}{2 \cdot 10} : - \frac{1}{5}

The solutions to the quadratic equation are:

x = \frac{5}{2}, x = - \frac{1}{5}

12 x^{2} + 96 x = 0

3 n^{2} + 12 n - 15 = 0

2 g^{2} = 4 (17 + 8) + g^{2}

x = 0.25 x^{2} - 14.5 x + 200

y, x = y^{2} - 8 y + 3

What are the solutions to the equation 10x^2=23x+5 ?
The solutions to the equation 10x^2=23x+5 are x= 5/2 ,x=-1/5
Find the zeros of 10x^2=23x+5
The zeros of 10x^2=23x+5 are x= 5/2 ,x=-1/5