What are the solutions to the equation quadraticformula x^2+4x=0 ?

The solutions to the equation quadraticformula x^2+4x=0 are x=0,x=-4

Find the zeros of quadraticformula x^2+4x=0

The zeros of quadraticformula x^2+4x=0 are x=0,x=-4

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x^{2} + 4 x = 0

x = 0, x = - 4

Solution steps

x^{2} + 4 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 0 = 4

x_{1, 2} = \frac{- 4 \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 4}{2 \cdot 1}, x_{2} = \frac{- 4 - 4}{2 \cdot 1}

x = \frac{- 4 + 4}{2 \cdot 1} : 0

x = \frac{- 4 - 4}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = 0, x = - 4

- x^{2} + 8 x - 5

x^{2} + 22 x - 5 = 0

x^{2} - 126 = 2 x + 1

60 = 50 + 20 \cdot t - 5 \cdot t^{2}

x^{2} + 32 x

What are the solutions to the equation quadraticformula x^2+4x=0 ?
The solutions to the equation quadraticformula x^2+4x=0 are x=0,x=-4
Find the zeros of quadraticformula x^2+4x=0
The zeros of quadraticformula x^2+4x=0 are x=0,x=-4