What are the solutions to the equation 3x^2+10x-88=0 ?

The solutions to the equation 3x^2+10x-88=0 are x=4,x=-22/3

Find the zeros of 3x^2+10x-88=0

The zeros of 3x^2+10x-88=0 are x=4,x=-22/3

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3 x^{2} + 10 x - 88 = 0

x = 4, x = - \frac{22}{3}

Solution steps

3 x^{2} + 10 x - 88 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 3 ( - 88 )}{2 \cdot 3}

1 0^{2} - 4 \cdot 3 (- 88) = 34

x_{1, 2} = \frac{- 10 \pm 34}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 10 + 34}{2 \cdot 3}, x_{2} = \frac{- 10 - 34}{2 \cdot 3}

x = \frac{- 10 + 34}{2 \cdot 3} : 4

x = \frac{- 10 - 34}{2 \cdot 3} : - \frac{22}{3}

The solutions to the quadratic equation are:

x = 4, x = - \frac{22}{3}

(x - 6)^{2} - 64 = 0

12 x^{2} - 4 x + 7 = 0

2 (x + 8)^{2} - 3 = 97

(\frac{3 a}{8})^{2} + a = 52

4 v^{2} + 6 v + 1 = 0

What are the solutions to the equation 3x^2+10x-88=0 ?
The solutions to the equation 3x^2+10x-88=0 are x=4,x=-22/3
Find the zeros of 3x^2+10x-88=0
The zeros of 3x^2+10x-88=0 are x=4,x=-22/3