What are the solutions to the equation 6x^2-19x-10=0 ?

The solutions to the equation 6x^2-19x-10=0 are x=(19+sqrt(601))/(12),x=(19-sqrt(601))/(12)

Find the zeros of 6x^2-19x-10=0

The zeros of 6x^2-19x-10=0 are x=(19+sqrt(601))/(12),x=(19-sqrt(601))/(12)

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6 x^{2} - 19 x - 10 = 0

x = \frac{19 + 601}{12}, x = \frac{19 - 601}{12}

Decimal Notation

x = 3.62627 \dots, x = - 0.45960 \dots

Solution steps

6 x^{2} - 19 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 19 ) \pm ( - 19 ) ^{2} - 4 \cdot 6 ( - 10 )}{2 \cdot 6}

(- 19)^{2} - 4 \cdot 6 (- 10) = 601

x_{1, 2} = \frac{- ( - 19 ) \pm 601}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 19 ) + 601}{2 \cdot 6}, x_{2} = \frac{- ( - 19 ) - 601}{2 \cdot 6}

x = \frac{- ( - 19 ) + 601}{2 \cdot 6} : \frac{19 + 601}{12}

x = \frac{- ( - 19 ) - 601}{2 \cdot 6} : \frac{19 - 601}{12}

The solutions to the quadratic equation are:

x = \frac{19 + 601}{12}, x = \frac{19 - 601}{12}

10 r^{2} + 68 r - 45 = 0

(x + 1)^{2} - 2 (x - 2)^{2} = 8

2 x^{2} + 6 x + 4 = 0

2 x (x + 4) = 42

Q^{2} - 10599.74 Q + 375000 = 0

What are the solutions to the equation 6x^2-19x-10=0 ?
The solutions to the equation 6x^2-19x-10=0 are x=(19+sqrt(601))/(12),x=(19-sqrt(601))/(12)
Find the zeros of 6x^2-19x-10=0
The zeros of 6x^2-19x-10=0 are x=(19+sqrt(601))/(12),x=(19-sqrt(601))/(12)