What are the solutions to the equation b^2= 3/4 ?

The solutions to the equation b^2= 3/4 are b=(sqrt(3))/2 ,b=-(sqrt(3))/2

Find the zeros of b^2= 3/4

The zeros of b^2= 3/4 are b=(sqrt(3))/2 ,b=-(sqrt(3))/2

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b^{2} = \frac{3}{4}

b = \frac{3}{2}, b = - \frac{3}{2}

Solution steps

b^{2} = \frac{3}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = \frac{3}{4}, b = - \frac{3}{4}

\frac{3}{4} = \frac{3}{2}

- \frac{3}{4} = - \frac{3}{2}

b = \frac{3}{2}, b = - \frac{3}{2}

(4 x - 3) (5 x - 7) = 0

x, - 3 = 4 x^{2} - x - 3

- 5 n^{2} + 2 n - 7 = 0

2 x^{2} + 7 x = 3

4 + 16.3 t - 4.9 t^{2} = 0

What are the solutions to the equation b^2= 3/4 ?
The solutions to the equation b^2= 3/4 are b=(sqrt(3))/2 ,b=-(sqrt(3))/2
Find the zeros of b^2= 3/4
The zeros of b^2= 3/4 are b=(sqrt(3))/2 ,b=-(sqrt(3))/2