What are the solutions to the equation ((3x+2)/4)^2=12 ?

The solutions to the equation ((3x+2)/4)^2=12 are x=(8sqrt(3)-2)/3 ,x=(-8sqrt(3)-2)/3

Find the zeros of ((3x+2)/4)^2=12

The zeros of ((3x+2)/4)^2=12 are x=(8sqrt(3)-2)/3 ,x=(-8sqrt(3)-2)/3

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(\frac{3 x + 2}{4})^{2} = 12

x = \frac{8 3 - 2}{3}, x = \frac{- 8 3 - 2}{3}

Decimal Notation

x = 3.95213 \dots, x = - 5.28546 \dots

Solution steps

(\frac{3 x + 2}{4})^{2} = 12

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

\frac{3 x + 2}{4} = 12 : x = \frac{8 3 - 2}{3}

Solve

\frac{3 x + 2}{4} = - 12 : x = \frac{- 8 3 - 2}{3}

The solutions to the quadratic equation are:

x = \frac{8 3 - 2}{3}, x = \frac{- 8 3 - 2}{3}

x + 3 = 4 x^{2}

p^{2} + 6 p - 72 = 0

(x - 6) (2 x + 4) = 0

9 = 0.0002 x^{2} - 0.316 x + 127.9

42 x^{2} - 13 x - 42 = 0

What are the solutions to the equation ((3x+2)/4)^2=12 ?
The solutions to the equation ((3x+2)/4)^2=12 are x=(8sqrt(3)-2)/3 ,x=(-8sqrt(3)-2)/3
Find the zeros of ((3x+2)/4)^2=12
The zeros of ((3x+2)/4)^2=12 are x=(8sqrt(3)-2)/3 ,x=(-8sqrt(3)-2)/3