What are the solutions to the equation 42x^2-13x-42=0 ?

The solutions to the equation 42x^2-13x-42=0 are x= 7/6 ,x=-6/7

Find the zeros of 42x^2-13x-42=0

The zeros of 42x^2-13x-42=0 are x= 7/6 ,x=-6/7

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42 x^{2} - 13 x - 42 = 0

x = \frac{7}{6}, x = - \frac{6}{7}

Solution steps

42 x^{2} - 13 x - 42 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 42 ( - 42 )}{2 \cdot 42}

(- 13)^{2} - 4 \cdot 42 (- 42) = 85

x_{1, 2} = \frac{- ( - 13 ) \pm 85}{2 \cdot 42}

Separate the solutions

x_{1} = \frac{- ( - 13 ) + 85}{2 \cdot 42}, x_{2} = \frac{- ( - 13 ) - 85}{2 \cdot 42}

x = \frac{- ( - 13 ) + 85}{2 \cdot 42} : \frac{7}{6}

x = \frac{- ( - 13 ) - 85}{2 \cdot 42} : - \frac{6}{7}

The solutions to the quadratic equation are:

x = \frac{7}{6}, x = - \frac{6}{7}

c^{2} = 8^{2} + 6^{2}

x, z = x^{2} + 9 y^{2}

x^{2} - 140 = 4

x, 6 x^{2} + 6 x - 6 x y = 0

3 x^{2} + 10 x - 77 = 0

What are the solutions to the equation 42x^2-13x-42=0 ?
The solutions to the equation 42x^2-13x-42=0 are x= 7/6 ,x=-6/7
Find the zeros of 42x^2-13x-42=0
The zeros of 42x^2-13x-42=0 are x= 7/6 ,x=-6/7