What are the solutions to the equation 3x^2+10x-77=0 ?

The solutions to the equation 3x^2+10x-77=0 are x= 11/3 ,x=-7

Find the zeros of 3x^2+10x-77=0

The zeros of 3x^2+10x-77=0 are x= 11/3 ,x=-7

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3 x^{2} + 10 x - 77 = 0

x = \frac{11}{3}, x = - 7

Solution steps

3 x^{2} + 10 x - 77 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 3 ( - 77 )}{2 \cdot 3}

1 0^{2} - 4 \cdot 3 (- 77) = 32

x_{1, 2} = \frac{- 10 \pm 32}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 10 + 32}{2 \cdot 3}, x_{2} = \frac{- 10 - 32}{2 \cdot 3}

x = \frac{- 10 + 32}{2 \cdot 3} : \frac{11}{3}

x = \frac{- 10 - 32}{2 \cdot 3} : - 7

The solutions to the quadratic equation are:

x = \frac{11}{3}, x = - 7

(x + 2)^{3} = x (x^{2} - 10 + 25)

6 x^{2} - 5 x = - 1

x^{2} - 9 x + \frac{5}{4} = 0

1 = (x - 4)^{2}

7.757 = π \cdot r^{2} \cdot 126

What are the solutions to the equation 3x^2+10x-77=0 ?
The solutions to the equation 3x^2+10x-77=0 are x= 11/3 ,x=-7
Find the zeros of 3x^2+10x-77=0
The zeros of 3x^2+10x-77=0 are x= 11/3 ,x=-7