What are the solutions to the equation 6x^2-5x=-1 ?

The solutions to the equation 6x^2-5x=-1 are x= 1/2 ,x= 1/3

Find the zeros of 6x^2-5x=-1

The zeros of 6x^2-5x=-1 are x= 1/2 ,x= 1/3

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6 x^{2} - 5 x = - 1

x = \frac{1}{2}, x = \frac{1}{3}

Solution steps

6 x^{2} - 5 x = - 1

Move

1

to the left side

6 x^{2} - 5 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 6 \cdot 1}{2 \cdot 6}

(- 5)^{2} - 4 \cdot 6 \cdot 1 = 1

x_{1, 2} = \frac{- ( - 5 ) \pm 1}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 1}{2 \cdot 6}, x_{2} = \frac{- ( - 5 ) - 1}{2 \cdot 6}

x = \frac{- ( - 5 ) + 1}{2 \cdot 6} : \frac{1}{2}

x = \frac{- ( - 5 ) - 1}{2 \cdot 6} : \frac{1}{3}

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = \frac{1}{3}

x^{2} - 9 x + \frac{5}{4} = 0

1 = (x - 4)^{2}

7.757 = π \cdot r^{2} \cdot 126

2 c^{2} - c - 15 = 0

2 (3 x^{2} - 2 x + 2) = 15 \cdot x^{2}

What are the solutions to the equation 6x^2-5x=-1 ?
The solutions to the equation 6x^2-5x=-1 are x= 1/2 ,x= 1/3
Find the zeros of 6x^2-5x=-1
The zeros of 6x^2-5x=-1 are x= 1/2 ,x= 1/3