What are the solutions to the equation x^2+(3x)^2=16 ?

The solutions to the equation x^2+(3x)^2=16 are x=(2sqrt(2))/(sqrt(5)),x=-(2sqrt(2))/(sqrt(5))

Find the zeros of x^2+(3x)^2=16

The zeros of x^2+(3x)^2=16 are x=(2sqrt(2))/(sqrt(5)),x=-(2sqrt(2))/(sqrt(5))

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x^{2} + (3 x)^{2} = 16

x = \frac{2 2}{5}, x = - \frac{2 2}{5}

Decimal Notation

x = 1.26491 \dots, x = - 1.26491 \dots

Solution steps

x^{2} + (3 x)^{2} = 16

Expand

x^{2} + (3 x)^{2} : 10 x^{2}

10 x^{2} = 16

Move

16

to the left side

10 x^{2} - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 10 ( - 16 )}{2 \cdot 10}

0^{2} - 4 \cdot 10 (- 16) = 810

x_{1, 2} = \frac{- 0 \pm 8 10}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- 0 + 8 10}{2 \cdot 10}, x_{2} = \frac{- 0 - 8 10}{2 \cdot 10}

x = \frac{- 0 + 8 10}{2 \cdot 10} : \frac{2 2}{5}

x = \frac{- 0 - 8 10}{2 \cdot 10} : - \frac{2 2}{5}

The solutions to the quadratic equation are:

x = \frac{2 2}{5}, x = - \frac{2 2}{5}

2 x^{2} + 5 x = 25

x^{2} = 2 x + 7

(x + 3) (x - 1) = - 3 x + 4

- x^{2} + 2 x - 15 = 0

x^{2} + x - 8

What are the solutions to the equation x^2+(3x)^2=16 ?
The solutions to the equation x^2+(3x)^2=16 are x=(2sqrt(2))/(sqrt(5)),x=-(2sqrt(2))/(sqrt(5))
Find the zeros of x^2+(3x)^2=16
The zeros of x^2+(3x)^2=16 are x=(2sqrt(2))/(sqrt(5)),x=-(2sqrt(2))/(sqrt(5))