What are the solutions to the equation 0=x^2-9x+8 ?

The solutions to the equation 0=x^2-9x+8 are x=8,x=1

Find the zeros of 0=x^2-9x+8

The zeros of 0=x^2-9x+8 are x=8,x=1

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0 = x^{2} - 9 x + 8

x = 8, x = 1

Solution steps

0 = x^{2} - 9 x + 8

Switch sides

x^{2} - 9 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot 8 = 7

x_{1, 2} = \frac{- ( - 9 ) \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 7}{2 \cdot 1}, x_{2} = \frac{- ( - 9 ) - 7}{2 \cdot 1}

x = \frac{- ( - 9 ) + 7}{2 \cdot 1} : 8

x = \frac{- ( - 9 ) - 7}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

x = 8, x = 1

y, 6 y^{2} d = 12

x, 8 x^{2} - k x + 2 = 0

4 x^{2} - 17 x + 3 = 0

2 x^{2} + 2 x = 0

x, x^{2} + y^{2} = - 3

What are the solutions to the equation 0=x^2-9x+8 ?
The solutions to the equation 0=x^2-9x+8 are x=8,x=1
Find the zeros of 0=x^2-9x+8
The zeros of 0=x^2-9x+8 are x=8,x=1