What are the solutions to the equation solvefor x,x^2+y^2=-3 ?

The solutions to the equation solvefor x,x^2+y^2=-3 are x=sqrt(-3-y^2),x=-sqrt(-3-y^2)

Find the zeros of solvefor x,x^2+y^2=-3

The zeros of solvefor x,x^2+y^2=-3 are x=sqrt(-3-y^2),x=-sqrt(-3-y^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solve for

x, x^{2} + y^{2} = - 3

x = - 3 - y^{2}, x = - - 3 - y^{2}

Solution steps

x^{2} + y^{2} = - 3

Move

y^{2}

to the right side

x^{2} = - 3 - y^{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 3 - y^{2}, x = - - 3 - y^{2}

3 x (x - 5) - (8 + 2 x) = 4 (x - 7) + 2 x

14 x^{2} + 1 = 6 x^{2} + 7 x

- 6 x^{2} + 2 x - 1 = 0

q^{2} + 11 q

2 x^{2} - 6 x - 11 = 0

What are the solutions to the equation solvefor x,x^2+y^2=-3 ?
The solutions to the equation solvefor x,x^2+y^2=-3 are x=sqrt(-3-y^2),x=-sqrt(-3-y^2)
Find the zeros of solvefor x,x^2+y^2=-3
The zeros of solvefor x,x^2+y^2=-3 are x=sqrt(-3-y^2),x=-sqrt(-3-y^2)