What are the solutions to the equation 14x^2+1=6x^2+7x ?

The solutions to the equation 14x^2+1=6x^2+7x are x=(7+sqrt(17))/(16),x=(7-sqrt(17))/(16)

Find the zeros of 14x^2+1=6x^2+7x

The zeros of 14x^2+1=6x^2+7x are x=(7+sqrt(17))/(16),x=(7-sqrt(17))/(16)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

14 x^{2} + 1 = 6 x^{2} + 7 x

x = \frac{7 + 17}{16}, x = \frac{7 - 17}{16}

Decimal Notation

x = 0.69519 \dots, x = 0.17980 \dots

Solution steps

14 x^{2} + 1 = 6 x^{2} + 7 x

Move

7 x

to the left side

14 x^{2} + 1 - 7 x = 6 x^{2}

Move

6 x^{2}

to the left side

8 x^{2} - 7 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 8 \cdot 1}{2 \cdot 8}

(- 7)^{2} - 4 \cdot 8 \cdot 1 = 17

x_{1, 2} = \frac{- ( - 7 ) \pm 17}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 17}{2 \cdot 8}, x_{2} = \frac{- ( - 7 ) - 17}{2 \cdot 8}

x = \frac{- ( - 7 ) + 17}{2 \cdot 8} : \frac{7 + 17}{16}

x = \frac{- ( - 7 ) - 17}{2 \cdot 8} : \frac{7 - 17}{16}

The solutions to the quadratic equation are:

x = \frac{7 + 17}{16}, x = \frac{7 - 17}{16}

- 6 x^{2} + 2 x - 1 = 0

q^{2} + 11 q

2 x^{2} - 6 x - 11 = 0

x + 2 = (x - 5) (x + 2)

2 x^{2} + 5 x = - 6

What are the solutions to the equation 14x^2+1=6x^2+7x ?
The solutions to the equation 14x^2+1=6x^2+7x are x=(7+sqrt(17))/(16),x=(7-sqrt(17))/(16)
Find the zeros of 14x^2+1=6x^2+7x
The zeros of 14x^2+1=6x^2+7x are x=(7+sqrt(17))/(16),x=(7-sqrt(17))/(16)