What are the solutions to the equation x^2=5-8x ?

The solutions to the equation x^2=5-8x are x=-4+sqrt(21),x=-4-sqrt(21)

Find the zeros of x^2=5-8x

The zeros of x^2=5-8x are x=-4+sqrt(21),x=-4-sqrt(21)

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x^{2} = 5 - 8 x

x = - 4 + 21, x = - 4 - 21

Solution steps

x^{2} = 5 - 8 x

Move

8 x

to the left side

x^{2} + 8 x = 5

Move

5

to the left side

x^{2} + 8 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 5) = 221

x_{1, 2} = \frac{- 8 \pm 2 21}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 2 21}{2 \cdot 1}, x_{2} = \frac{- 8 - 2 21}{2 \cdot 1}

x = \frac{- 8 + 2 21}{2 \cdot 1} : - 4 + 21

x = \frac{- 8 - 2 21}{2 \cdot 1} : - 4 - 21

The solutions to the quadratic equation are:

x = - 4 + 21, x = - 4 - 21

20 \cdot 5 - 19 = r^{2}

4 y^{2} + 15 y + 6 = 4 y

p^{2} + 0.2 p - 0.96 = 0

v^{2} = 256

(19 x - 2 x) (35 - 2 x) = 465

What are the solutions to the equation x^2=5-8x ?
The solutions to the equation x^2=5-8x are x=-4+sqrt(21),x=-4-sqrt(21)
Find the zeros of x^2=5-8x
The zeros of x^2=5-8x are x=-4+sqrt(21),x=-4-sqrt(21)