What are the solutions to the equation 4y^2+15y+6=4y ?

The solutions to the equation 4y^2+15y+6=4y are y=-3/4 ,y=-2

Find the zeros of 4y^2+15y+6=4y

The zeros of 4y^2+15y+6=4y are y=-3/4 ,y=-2

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4 y^{2} + 15 y + 6 = 4 y

y = - \frac{3}{4}, y = - 2

Decimal Notation

y = - 0.75, y = - 2

Solution steps

4 y^{2} + 15 y + 6 = 4 y

Move

4 y

to the left side

4 y^{2} + 11 y + 6 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 4 \cdot 6}{2 \cdot 4}

1 1^{2} - 4 \cdot 4 \cdot 6 = 5

y_{1, 2} = \frac{- 11 \pm 5}{2 \cdot 4}

Separate the solutions

y_{1} = \frac{- 11 + 5}{2 \cdot 4}, y_{2} = \frac{- 11 - 5}{2 \cdot 4}

y = \frac{- 11 + 5}{2 \cdot 4} : - \frac{3}{4}

y = \frac{- 11 - 5}{2 \cdot 4} : - 2

The solutions to the quadratic equation are:

y = - \frac{3}{4}, y = - 2

p^{2} + 0.2 p - 0.96 = 0

v^{2} = 256

(19 x - 2 x) (35 - 2 x) = 465

2 (3 x)^{2} = 162

44 = 1.5 (\frac{2}{3}) v + 0.06 v^{2}

What are the solutions to the equation 4y^2+15y+6=4y ?
The solutions to the equation 4y^2+15y+6=4y are y=-3/4 ,y=-2
Find the zeros of 4y^2+15y+6=4y
The zeros of 4y^2+15y+6=4y are y=-3/4 ,y=-2