What are the solutions to the equation 2(3x)^2=162 ?

The solutions to the equation 2(3x)^2=162 are x=3,x=-3

Find the zeros of 2(3x)^2=162

The zeros of 2(3x)^2=162 are x=3,x=-3

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2 (3 x)^{2} = 162

x = 3, x = - 3

Solution steps

2 (3 x)^{2} = 162

Divide both sides by

2

(3 x)^{2} = 81

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x = 81 : x = 3

Solve

3 x = - 81 : x = - 3

The solutions to the quadratic equation are:

x = 3, x = - 3

44 = 1.5 (\frac{2}{3}) v + 0.06 v^{2}

m + 1 = - 4 m^{2}

1 6^{2} = 1 2^{2} + x^{2}

8 x - 10 = x^{2} - 2 x

x^{2} + 10 - 24 = 0

What are the solutions to the equation 2(3x)^2=162 ?
The solutions to the equation 2(3x)^2=162 are x=3,x=-3
Find the zeros of 2(3x)^2=162
The zeros of 2(3x)^2=162 are x=3,x=-3