What are the solutions to the equation 16^2=12^2+x^2 ?

The solutions to the equation 16^2=12^2+x^2 are x=4sqrt(7),x=-4sqrt(7)

Find the zeros of 16^2=12^2+x^2

The zeros of 16^2=12^2+x^2 are x=4sqrt(7),x=-4sqrt(7)

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1 6^{2} = 1 2^{2} + x^{2}

x = 47, x = - 47

Decimal Notation

x = 10.58300 \dots, x = - 10.58300 \dots

Solution steps

1 6^{2} = 1 2^{2} + x^{2}

Switch sides

1 2^{2} + x^{2} = 1 6^{2}

Move

1 2^{2}

to the right side

x^{2} = 112

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 112, x = - 112

112 = 47

- 112 = - 47

x = 47, x = - 47

8 x - 10 = x^{2} - 2 x

x^{2} + 10 - 24 = 0

2 x^{2} - 8 x + 24 = 0

7 x^{2} + 42 x - 112 = 0

3 x^{2} - 12 = 0

What are the solutions to the equation 16^2=12^2+x^2 ?
The solutions to the equation 16^2=12^2+x^2 are x=4sqrt(7),x=-4sqrt(7)
Find the zeros of 16^2=12^2+x^2
The zeros of 16^2=12^2+x^2 are x=4sqrt(7),x=-4sqrt(7)