What are the solutions to the equation 2x-x^2-3=0 ?

The solutions to the equation 2x-x^2-3=0 are x=1-sqrt(2)i,x=1+sqrt(2)i

Find the zeros of 2x-x^2-3=0

The zeros of 2x-x^2-3=0 are x=1-sqrt(2)i,x=1+sqrt(2)i

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2 x - x^{2} - 3 = 0

x = 1 - 2 i, x = 1 + 2 i

Solution steps

2 x - x^{2} - 3 = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} + 2 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 1 ) ( - 3 )}{2 ( - 1 )}

Simplify

2^{2} - 4 (- 1) (- 3) : 22 i

x_{1, 2} = \frac{- 2 \pm 2 2 i}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 2 + 2 2 i}{2 ( - 1 )}, x_{2} = \frac{- 2 - 2 2 i}{2 ( - 1 )}

x = \frac{- 2 + 2 2 i}{2 ( - 1 )} : 1 - 2 i

x = \frac{- 2 - 2 2 i}{2 ( - 1 )} : 1 + 2 i

The solutions to the quadratic equation are:

x = 1 - 2 i, x = 1 + 2 i

3 x + 3 x^{2} = 0

(w - 6) (w - 9) = 0

5 a^{2} - 11 a = 45

x, x^{2} - 4 x - 16 = - 4 x

w^{2} - w + 1 = 0

What are the solutions to the equation 2x-x^2-3=0 ?
The solutions to the equation 2x-x^2-3=0 are x=1-sqrt(2)i,x=1+sqrt(2)i
Find the zeros of 2x-x^2-3=0
The zeros of 2x-x^2-3=0 are x=1-sqrt(2)i,x=1+sqrt(2)i