What are the solutions to the equation a^2-14a+45=0 ?

The solutions to the equation a^2-14a+45=0 are a=9,a=5

Find the zeros of a^2-14a+45=0

The zeros of a^2-14a+45=0 are a=9,a=5

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a^{2} - 14 a + 45 = 0

a = 9, a = 5

Solution steps

a^{2} - 14 a + 45 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 45}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot 45 = 4

a_{1, 2} = \frac{- ( - 14 ) \pm 4}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 14 ) + 4}{2 \cdot 1}, a_{2} = \frac{- ( - 14 ) - 4}{2 \cdot 1}

a = \frac{- ( - 14 ) + 4}{2 \cdot 1} : 9

a = \frac{- ( - 14 ) - 4}{2 \cdot 1} : 5

The solutions to the quadratic equation are:

a = 9, a = 5

x, (L - x)^{2} = 4 x^{2}

(w - 3) (w - 5) = 0

2 x^{2} - 4 x - 5

x^{2} = 7 x + 60

4 x^{2} + 38 x + 18 = 0

What are the solutions to the equation a^2-14a+45=0 ?
The solutions to the equation a^2-14a+45=0 are a=9,a=5
Find the zeros of a^2-14a+45=0
The zeros of a^2-14a+45=0 are a=9,a=5