What are the solutions to the equation 4x^2+38x+18=0 ?

The solutions to the equation 4x^2+38x+18=0 are x=-1/2 ,x=-9

Find the zeros of 4x^2+38x+18=0

The zeros of 4x^2+38x+18=0 are x=-1/2 ,x=-9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} + 38 x + 18 = 0

x = - \frac{1}{2}, x = - 9

Decimal Notation

x = - 0.5, x = - 9

Solution steps

4 x^{2} + 38 x + 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 38 \pm 3 8 ^{2} - 4 \cdot 4 \cdot 18}{2 \cdot 4}

3 8^{2} - 4 \cdot 4 \cdot 18 = 34

x_{1, 2} = \frac{- 38 \pm 34}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 38 + 34}{2 \cdot 4}, x_{2} = \frac{- 38 - 34}{2 \cdot 4}

x = \frac{- 38 + 34}{2 \cdot 4} : - \frac{1}{2}

x = \frac{- 38 - 34}{2 \cdot 4} : - 9

The solutions to the quadratic equation are:

x = - \frac{1}{2}, x = - 9

5 x^{2} - 20 x - 300 = 0

p^{2} + p - 20 = 0

(x + 5) (x - 6) = 1

3 x^{2} - 14 x - 13 = 2 x^{2}

x^{2} - 3 x = 3 x^{2} - 5 x - 24

What are the solutions to the equation 4x^2+38x+18=0 ?
The solutions to the equation 4x^2+38x+18=0 are x=-1/2 ,x=-9
Find the zeros of 4x^2+38x+18=0
The zeros of 4x^2+38x+18=0 are x=-1/2 ,x=-9