What are the solutions to the equation 8^2=6^2+x^2 ?

The solutions to the equation 8^2=6^2+x^2 are x=2sqrt(7),x=-2sqrt(7)

Find the zeros of 8^2=6^2+x^2

The zeros of 8^2=6^2+x^2 are x=2sqrt(7),x=-2sqrt(7)

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8^{2} = 6^{2} + x^{2}

x = 27, x = - 27

Decimal Notation

x = 5.29150 \dots, x = - 5.29150 \dots

Solution steps

8^{2} = 6^{2} + x^{2}

Switch sides

6^{2} + x^{2} = 8^{2}

Move

6^{2}

to the right side

x^{2} = 28

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 28, x = - 28

28 = 27

- 28 = - 27

x = 27, x = - 27

x (x - 7) + 12 = 0

2 (x + 5)^{2} - 32 = 0

2 x^{2} - (k - 1) x - k = 0

3 y^{2} = 81

x, 4 x^{2} y + 1 = 9

What are the solutions to the equation 8^2=6^2+x^2 ?
The solutions to the equation 8^2=6^2+x^2 are x=2sqrt(7),x=-2sqrt(7)
Find the zeros of 8^2=6^2+x^2
The zeros of 8^2=6^2+x^2 are x=2sqrt(7),x=-2sqrt(7)