What are the solutions to the equation 2(x+5)^2-32=0 ?

The solutions to the equation 2(x+5)^2-32=0 are x=-1,x=-9

Find the zeros of 2(x+5)^2-32=0

The zeros of 2(x+5)^2-32=0 are x=-1,x=-9

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2 (x + 5)^{2} - 32 = 0

x = - 1, x = - 9

Solution steps

2 (x + 5)^{2} - 32 = 0

Move

32

to the right side

2 (x + 5)^{2} = 32

Divide both sides by

2

(x + 5)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 5 = 16 : x = - 1

Solve

x + 5 = - 16 : x = - 9

The solutions to the quadratic equation are:

x = - 1, x = - 9

2 x^{2} - (k - 1) x - k = 0

3 y^{2} = 81

x, 4 x^{2} y + 1 = 9

x^{2} + 11 x + 15 = 0

4 \cdot (2 x + 5) + x \cdot (2 x + 5) = 0

What are the solutions to the equation 2(x+5)^2-32=0 ?
The solutions to the equation 2(x+5)^2-32=0 are x=-1,x=-9
Find the zeros of 2(x+5)^2-32=0
The zeros of 2(x+5)^2-32=0 are x=-1,x=-9