What are the solutions to the equation 4*(2x+5)+x*(2x+5)=0 ?

The solutions to the equation 4*(2x+5)+x*(2x+5)=0 are x=-5/2 ,x=-4

Find the zeros of 4*(2x+5)+x*(2x+5)=0

The zeros of 4*(2x+5)+x*(2x+5)=0 are x=-5/2 ,x=-4

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4 \cdot (2 x + 5) + x \cdot (2 x + 5) = 0

x = - \frac{5}{2}, x = - 4

Decimal Notation

x = - 2.5, x = - 4

Solution steps

4 (2 x + 5) + x (2 x + 5) = 0

Expand

4 (2 x + 5) + x (2 x + 5) : 2 x^{2} + 13 x + 20

2 x^{2} + 13 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 2 \cdot 20}{2 \cdot 2}

1 3^{2} - 4 \cdot 2 \cdot 20 = 3

x_{1, 2} = \frac{- 13 \pm 3}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 13 + 3}{2 \cdot 2}, x_{2} = \frac{- 13 - 3}{2 \cdot 2}

x = \frac{- 13 + 3}{2 \cdot 2} : - \frac{5}{2}

x = \frac{- 13 - 3}{2 \cdot 2} : - 4

The solutions to the quadratic equation are:

x = - \frac{5}{2}, x = - 4

(m + 6) (m - 3) = - 18

- 8 x^{2} - 6 = - x^{2} + 2 x + 1

1.3 x^{2} - 4 x = 3.5

x, C x^{2} + x + y^{2} = 0

x^{2} - 8 x + 16 = - 12

What are the solutions to the equation 4*(2x+5)+x*(2x+5)=0 ?
The solutions to the equation 4*(2x+5)+x*(2x+5)=0 are x=-5/2 ,x=-4
Find the zeros of 4*(2x+5)+x*(2x+5)=0
The zeros of 4*(2x+5)+x*(2x+5)=0 are x=-5/2 ,x=-4