What are the solutions to the equation 29x^2-3=8-20x^2 ?

The solutions to the equation 29x^2-3=8-20x^2 are x=(sqrt(11))/7 ,x=-(sqrt(11))/7

Find the zeros of 29x^2-3=8-20x^2

The zeros of 29x^2-3=8-20x^2 are x=(sqrt(11))/7 ,x=-(sqrt(11))/7

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29 x^{2} - 3 = 8 - 20 x^{2}

x = \frac{11}{7}, x = - \frac{11}{7}

Decimal Notation

x = 0.47380 \dots, x = - 0.47380 \dots

Solution steps

29 x^{2} - 3 = 8 - 20 x^{2}

Move

3

to the right side

29 x^{2} = - 20 x^{2} + 11

Move

20 x^{2}

to the left side

49 x^{2} = 11

Divide both sides by

49

x^{2} = \frac{11}{49}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{11}{49}, x = - \frac{11}{49}

\frac{11}{49} = \frac{11}{7}

- \frac{11}{49} = - \frac{11}{7}

x = \frac{11}{7}, x = - \frac{11}{7}

y, x^{2} - y^{2} = x

4 x^{2} + 2 x - 9 = (x - 2) (x - 9)

32 x^{2} + 32 = 0

(x + 4)^{2} = 9 x + 22

x^{2} + 1 = 13

What are the solutions to the equation 29x^2-3=8-20x^2 ?
The solutions to the equation 29x^2-3=8-20x^2 are x=(sqrt(11))/7 ,x=-(sqrt(11))/7
Find the zeros of 29x^2-3=8-20x^2
The zeros of 29x^2-3=8-20x^2 are x=(sqrt(11))/7 ,x=-(sqrt(11))/7