What are the solutions to the equation 32x^2+32=0 ?

The solutions to the equation 32x^2+32=0 are x=i,x=-i

Find the zeros of 32x^2+32=0

The zeros of 32x^2+32=0 are x=i,x=-i

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32 x^{2} + 32 = 0

x = i, x = - i

Solution steps

32 x^{2} + 32 = 0

Move

32

to the right side

32 x^{2} = - 32

Divide both sides by

32

x^{2} = - 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 1, x = - - 1

- 1 = i

- - 1 = - i

x = i, x = - i

(x + 4)^{2} = 9 x + 22

x^{2} + 1 = 13

3 x^{2} + 8 = 10 x

2 x^{2} - 8 x - 7 = 0

3 x^{2} = 4 x + 7

What are the solutions to the equation 32x^2+32=0 ?
The solutions to the equation 32x^2+32=0 are x=i,x=-i
Find the zeros of 32x^2+32=0
The zeros of 32x^2+32=0 are x=i,x=-i