What are the solutions to the equation 1xx+15x+515=0 ?

The solutions to the equation 1xx+15x+515=0 are x=-15/2+i(sqrt(1835))/2 ,x=-15/2-i(sqrt(1835))/2

Find the zeros of 1xx+15x+515=0

The zeros of 1xx+15x+515=0 are x=-15/2+i(sqrt(1835))/2 ,x=-15/2-i(sqrt(1835))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

1 xx + 15 x + 515 = 0

x = - \frac{15}{2} + i \frac{1835}{2}, x = - \frac{15}{2} - i \frac{1835}{2}

Solution steps

1 \cdot xx + 15 x + 515 = 0

Expand

1 \cdot xx + 15 x + 515 : x^{2} + 15 x + 515

x^{2} + 15 x + 515 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 1 \cdot 515}{2 \cdot 1}

Simplify

1 5^{2} - 4 \cdot 1 \cdot 515 : 1835 i

x_{1, 2} = \frac{- 15 \pm 1835 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 15 + 1835 i}{2 \cdot 1}, x_{2} = \frac{- 15 - 1835 i}{2 \cdot 1}

x = \frac{- 15 + 1835 i}{2 \cdot 1} : - \frac{15}{2} + i \frac{1835}{2}

x = \frac{- 15 - 1835 i}{2 \cdot 1} : - \frac{15}{2} - i \frac{1835}{2}

The solutions to the quadratic equation are:

x = - \frac{15}{2} + i \frac{1835}{2}, x = - \frac{15}{2} - i \frac{1835}{2}

x^{2} - 8 x = 15

3 x^{2} - 4 = - 5 x

3 d^{2} - 4 d = 0

3 x^{2} + 2 x - 14 = 0

8 x^{2} + 9 = 0

What are the solutions to the equation 1xx+15x+515=0 ?
The solutions to the equation 1xx+15x+515=0 are x=-15/2+i(sqrt(1835))/2 ,x=-15/2-i(sqrt(1835))/2
Find the zeros of 1xx+15x+515=0
The zeros of 1xx+15x+515=0 are x=-15/2+i(sqrt(1835))/2 ,x=-15/2-i(sqrt(1835))/2