What are the solutions to the equation z^2+6z+4=0 ?

The solutions to the equation z^2+6z+4=0 are z=-3+sqrt(5),z=-3-sqrt(5)

Find the zeros of z^2+6z+4=0

The zeros of z^2+6z+4=0 are z=-3+sqrt(5),z=-3-sqrt(5)

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z^{2} + 6 z + 4 = 0

z = - 3 + 5, z = - 3 - 5

Decimal Notation

z = - 0.76393 \dots, z = - 5.23606 \dots

Solution steps

z^{2} + 6 z + 4 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot 4 = 25

z_{1, 2} = \frac{- 6 \pm 2 5}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- 6 + 2 5}{2 \cdot 1}, z_{2} = \frac{- 6 - 2 5}{2 \cdot 1}

z = \frac{- 6 + 2 5}{2 \cdot 1} : - 3 + 5

z = \frac{- 6 - 2 5}{2 \cdot 1} : - 3 - 5

The solutions to the quadratic equation are:

z = - 3 + 5, z = - 3 - 5

- 0.5 x^{2} + 18 = - 6 x + 33

25 x^{2} - 2 = 0

x^{2} = 2 x (5 k + 1) - 8 (3 k + 5)

m^{2} - 5 = 4

x^{2} + 7 = 6

What are the solutions to the equation z^2+6z+4=0 ?
The solutions to the equation z^2+6z+4=0 are z=-3+sqrt(5),z=-3-sqrt(5)
Find the zeros of z^2+6z+4=0
The zeros of z^2+6z+4=0 are z=-3+sqrt(5),z=-3-sqrt(5)