What are the solutions to the equation factor 2w^2-7w-4=0 ?

The solutions to the equation factor 2w^2-7w-4=0 are w=-1/2 ,w=4

Find the zeros of factor 2w^2-7w-4=0

The zeros of factor 2w^2-7w-4=0 are w=-1/2 ,w=4

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2 w^{2} - 7 w - 4 = 0

w = - \frac{1}{2}, w = 4

Decimal Notation

w = - 0.5, w = 4

Solution steps

2 w^{2} - 7 w - 4 = 0

Factor

2 w^{2} - 7 w - 4 : (2 w + 1) (w - 4)

(2 w + 1) (w - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 w + 1 = 0 or w - 4 = 0

Solve

2 w + 1 = 0 : w = - \frac{1}{2}

Solve

w - 4 = 0 : w = 4

The solutions to the quadratic equation are:

w = - \frac{1}{2}, w = 4

(x + 3)^{2} + 4 (x + 2)^{2} = 2 5^{2}

5 = 3 x^{2}

x, x^{2} - 10 x + 20 = 0

(3 - 2 x)^{2} = 7

2 x^{2} = - 4 x

What are the solutions to the equation factor 2w^2-7w-4=0 ?
The solutions to the equation factor 2w^2-7w-4=0 are w=-1/2 ,w=4
Find the zeros of factor 2w^2-7w-4=0
The zeros of factor 2w^2-7w-4=0 are w=-1/2 ,w=4