What are the solutions to the equation (3-2x)^2=7 ?

The solutions to the equation (3-2x)^2=7 are x=(3-sqrt(7))/2 ,x=(3+sqrt(7))/2

Find the zeros of (3-2x)^2=7

The zeros of (3-2x)^2=7 are x=(3-sqrt(7))/2 ,x=(3+sqrt(7))/2

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(3 - 2 x)^{2} = 7

x = \frac{3 - 7}{2}, x = \frac{3 + 7}{2}

Decimal Notation

x = 0.17712 \dots, x = 2.82287 \dots

Solution steps

(3 - 2 x)^{2} = 7

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 - 2 x = 7 : x = \frac{3 - 7}{2}

Solve

3 - 2 x = - 7 : x = \frac{3 + 7}{2}

The solutions to the quadratic equation are:

x = \frac{3 - 7}{2}, x = \frac{3 + 7}{2}

2 x^{2} = - 4 x

y^{2} - 15 y = - 54

1 + 10 x - 0.9 x^{2} = 0

x^{2} + 5 = 8

4 w^{2} - 7 w + 6 = 5

What are the solutions to the equation (3-2x)^2=7 ?
The solutions to the equation (3-2x)^2=7 are x=(3-sqrt(7))/2 ,x=(3+sqrt(7))/2
Find the zeros of (3-2x)^2=7
The zeros of (3-2x)^2=7 are x=(3-sqrt(7))/2 ,x=(3+sqrt(7))/2