What are the solutions to the equation 4w^2-7w+6=5 ?

The solutions to the equation 4w^2-7w+6=5 are w=(7+sqrt(33))/8 ,w=(7-sqrt(33))/8

Find the zeros of 4w^2-7w+6=5

The zeros of 4w^2-7w+6=5 are w=(7+sqrt(33))/8 ,w=(7-sqrt(33))/8

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4 w^{2} - 7 w + 6 = 5

w = \frac{7 + 33}{8}, w = \frac{7 - 33}{8}

Decimal Notation

w = 1.59307 \dots, w = 0.15692 \dots

Solution steps

4 w^{2} - 7 w + 6 = 5

Move

5

to the left side

4 w^{2} - 7 w + 1 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 4 \cdot 1}{2 \cdot 4}

(- 7)^{2} - 4 \cdot 4 \cdot 1 = 33

w_{1, 2} = \frac{- ( - 7 ) \pm 33}{2 \cdot 4}

Separate the solutions

w_{1} = \frac{- ( - 7 ) + 33}{2 \cdot 4}, w_{2} = \frac{- ( - 7 ) - 33}{2 \cdot 4}

w = \frac{- ( - 7 ) + 33}{2 \cdot 4} : \frac{7 + 33}{8}

w = \frac{- ( - 7 ) - 33}{2 \cdot 4} : \frac{7 - 33}{8}

The solutions to the quadratic equation are:

w = \frac{7 + 33}{8}, w = \frac{7 - 33}{8}

(5 - x)^{2} = 0

- 2 s^{2} + 8 s - 4 = 0

x, x^{2} - 3 x + 2 = y

x^{2} + 3 = 9

2 x^{2} - 8 x - 5

What are the solutions to the equation 4w^2-7w+6=5 ?
The solutions to the equation 4w^2-7w+6=5 are w=(7+sqrt(33))/8 ,w=(7-sqrt(33))/8
Find the zeros of 4w^2-7w+6=5
The zeros of 4w^2-7w+6=5 are w=(7+sqrt(33))/8 ,w=(7-sqrt(33))/8