What are the solutions to the equation -3x^2-42x-375=-12 ?

The solutions to the equation -3x^2-42x-375=-12 are x=-7-6sqrt(2)i,x=-7+6sqrt(2)i

Find the zeros of -3x^2-42x-375=-12

The zeros of -3x^2-42x-375=-12 are x=-7-6sqrt(2)i,x=-7+6sqrt(2)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 3 x^{2} - 42 x - 375 = - 12

x = - 7 - 62 i, x = - 7 + 62 i

Solution steps

- 3 x^{2} - 42 x - 375 = - 12

Move

12

to the left side

- 3 x^{2} - 42 x - 363 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 42 ) \pm ( - 42 ) ^{2} - 4 ( - 3 ) ( - 363 )}{2 ( - 3 )}

Simplify

(- 42)^{2} - 4 (- 3) (- 363) : 362 i

x_{1, 2} = \frac{- ( - 42 ) \pm 36 2 i}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- ( - 42 ) + 36 2 i}{2 ( - 3 )}, x_{2} = \frac{- ( - 42 ) - 36 2 i}{2 ( - 3 )}

x = \frac{- ( - 42 ) + 36 2 i}{2 ( - 3 )} : - 7 - 62 i

x = \frac{- ( - 42 ) - 36 2 i}{2 ( - 3 )} : - 7 + 62 i

The solutions to the quadratic equation are:

x = - 7 - 62 i, x = - 7 + 62 i

(x - 6) (x - 10) = - 4

Q^{2} - 3092.8 Q + 120000 = 0

- 3 x^{2} - 18 x + 2 = 0

6 x - 12 = - 2 (x + 3) 2 + (2 x + 3) (x - 5)

- 30 - 13 x - 15 x^{2} = 0

What are the solutions to the equation -3x^2-42x-375=-12 ?
The solutions to the equation -3x^2-42x-375=-12 are x=-7-6sqrt(2)i,x=-7+6sqrt(2)i
Find the zeros of -3x^2-42x-375=-12
The zeros of -3x^2-42x-375=-12 are x=-7-6sqrt(2)i,x=-7+6sqrt(2)i