What are the solutions to the equation x^2+16x+56=0 ?

The solutions to the equation x^2+16x+56=0 are x=2(sqrt(2)-4),x=-2(4+sqrt(2))

Find the zeros of x^2+16x+56=0

The zeros of x^2+16x+56=0 are x=2(sqrt(2)-4),x=-2(4+sqrt(2))

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x^{2} + 16 x + 56 = 0

x = 2 (2 - 4), x = - 2 (4 + 2)

Decimal Notation

x = - 5.17157 \dots, x = - 10.82842 \dots

Solution steps

x^{2} + 16 x + 56 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot 56}{2 \cdot 1}

1 6^{2} - 4 \cdot 1 \cdot 56 = 42

x_{1, 2} = \frac{- 16 \pm 4 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 16 + 4 2}{2 \cdot 1}, x_{2} = \frac{- 16 - 4 2}{2 \cdot 1}

x = \frac{- 16 + 4 2}{2 \cdot 1} : 2 (2 - 4)

x = \frac{- 16 - 4 2}{2 \cdot 1} : - 2 (4 + 2)

The solutions to the quadratic equation are:

x = 2 (2 - 4), x = - 2 (4 + 2)

12 x^{2} + 23 x - 24 = 0

5 (x - 3)^{2} = 30

2 m^{2} - 10 m + 12 = 0

(2 x - 1) (x + 3) = 2 x

0.99 = 2 x - x^{2}

What are the solutions to the equation x^2+16x+56=0 ?
The solutions to the equation x^2+16x+56=0 are x=2(sqrt(2)-4),x=-2(4+sqrt(2))
Find the zeros of x^2+16x+56=0
The zeros of x^2+16x+56=0 are x=2(sqrt(2)-4),x=-2(4+sqrt(2))