What are the solutions to the equation 2m^2-10m+12=0 ?

The solutions to the equation 2m^2-10m+12=0 are m=3,m=2

Find the zeros of 2m^2-10m+12=0

The zeros of 2m^2-10m+12=0 are m=3,m=2

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2 m^{2} - 10 m + 12 = 0

m = 3, m = 2

Solution steps

2 m^{2} - 10 m + 12 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 2 \cdot 12}{2 \cdot 2}

(- 10)^{2} - 4 \cdot 2 \cdot 12 = 2

m_{1, 2} = \frac{- ( - 10 ) \pm 2}{2 \cdot 2}

Separate the solutions

m_{1} = \frac{- ( - 10 ) + 2}{2 \cdot 2}, m_{2} = \frac{- ( - 10 ) - 2}{2 \cdot 2}

m = \frac{- ( - 10 ) + 2}{2 \cdot 2} : 3

m = \frac{- ( - 10 ) - 2}{2 \cdot 2} : 2

The solutions to the quadratic equation are:

m = 3, m = 2

(2 x - 1) (x + 3) = 2 x

0.99 = 2 x - x^{2}

x^{2} + (2 x - 2)^{2} = x + 6

8 (x^{2} - x) = x^{2} - 3

16 x^{2} + 16 x = - 4

What are the solutions to the equation 2m^2-10m+12=0 ?
The solutions to the equation 2m^2-10m+12=0 are m=3,m=2
Find the zeros of 2m^2-10m+12=0
The zeros of 2m^2-10m+12=0 are m=3,m=2