What are the solutions to the equation 7x+x^2-18=0 ?

The solutions to the equation 7x+x^2-18=0 are x=2,x=-9

Find the zeros of 7x+x^2-18=0

The zeros of 7x+x^2-18=0 are x=2,x=-9

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7 x + x^{2} - 18 = 0

x = 2, x = - 9

Solution steps

7 x + x^{2} - 18 = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 7 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot ( - 18 )}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot (- 18) = 11

x_{1, 2} = \frac{- 7 \pm 11}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 7 + 11}{2 \cdot 1}, x_{2} = \frac{- 7 - 11}{2 \cdot 1}

x = \frac{- 7 + 11}{2 \cdot 1} : 2

x = \frac{- 7 - 11}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

x = 2, x = - 9

3 x^{2} + 2 x - 5 = 2 x^{2} - 2

(2 x - 3) (x + c) = a x^{2} + b x - 12

3 x^{2} + x - 2 = 0

x^{2} = 7 x + 6

(x - 7)^{2} = - 4

What are the solutions to the equation 7x+x^2-18=0 ?
The solutions to the equation 7x+x^2-18=0 are x=2,x=-9
Find the zeros of 7x+x^2-18=0
The zeros of 7x+x^2-18=0 are x=2,x=-9