What are the solutions to the equation 3x^2+4x=8 ?

The solutions to the equation 3x^2+4x=8 are x=(2(sqrt(7)-1))/3 ,x=-(2(1+sqrt(7)))/3

Find the zeros of 3x^2+4x=8

The zeros of 3x^2+4x=8 are x=(2(sqrt(7)-1))/3 ,x=-(2(1+sqrt(7)))/3

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3 x^{2} + 4 x = 8

x = \frac{2 ( 7 - 1 )}{3}, x = - \frac{2 ( 1 + 7 )}{3}

Decimal Notation

x = 1.09716 \dots, x = - 2.43050 \dots

Solution steps

3 x^{2} + 4 x = 8

Move

8

to the left side

3 x^{2} + 4 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 3 ( - 8 )}{2 \cdot 3}

4^{2} - 4 \cdot 3 (- 8) = 47

x_{1, 2} = \frac{- 4 \pm 4 7}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 4 + 4 7}{2 \cdot 3}, x_{2} = \frac{- 4 - 4 7}{2 \cdot 3}

x = \frac{- 4 + 4 7}{2 \cdot 3} : \frac{2 ( 7 - 1 )}{3}

x = \frac{- 4 - 4 7}{2 \cdot 3} : - \frac{2 ( 1 + 7 )}{3}

The solutions to the quadratic equation are:

x = \frac{2 ( 7 - 1 )}{3}, x = - \frac{2 ( 1 + 7 )}{3}

5 x^{2} + 8 x - 17 = 0

16 = - 2.7 t^{2} + 60 t + 6.5

(3 y)^{2} = - 18

x^{2} + 14 x - 2 = 0

36 x^{2} = - 60 x - 25

What are the solutions to the equation 3x^2+4x=8 ?
The solutions to the equation 3x^2+4x=8 are x=(2(sqrt(7)-1))/3 ,x=-(2(1+sqrt(7)))/3
Find the zeros of 3x^2+4x=8
The zeros of 3x^2+4x=8 are x=(2(sqrt(7)-1))/3 ,x=-(2(1+sqrt(7)))/3