What are the solutions to the equation 24x^2+28x+4=0 ?

The solutions to the equation 24x^2+28x+4=0 are x=-1/6 ,x=-1

Find the zeros of 24x^2+28x+4=0

The zeros of 24x^2+28x+4=0 are x=-1/6 ,x=-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

24 x^{2} + 28 x + 4 = 0

x = - \frac{1}{6}, x = - 1

Decimal Notation

x = - 0.16666 \dots, x = - 1

Solution steps

24 x^{2} + 28 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 28 \pm 2 8 ^{2} - 4 \cdot 24 \cdot 4}{2 \cdot 24}

2 8^{2} - 4 \cdot 24 \cdot 4 = 20

x_{1, 2} = \frac{- 28 \pm 20}{2 \cdot 24}

Separate the solutions

x_{1} = \frac{- 28 + 20}{2 \cdot 24}, x_{2} = \frac{- 28 - 20}{2 \cdot 24}

x = \frac{- 28 + 20}{2 \cdot 24} : - \frac{1}{6}

x = \frac{- 28 - 20}{2 \cdot 24} : - 1

The solutions to the quadratic equation are:

x = - \frac{1}{6}, x = - 1

20 x^{2} - 5 = 0

x^{2} = 6 x - 66

x = x^{2} - 2 x - 3

4 x^{2} - 20 x - 24 = 0

- 2 x^{2} + 4 x - 12 = 0

What are the solutions to the equation 24x^2+28x+4=0 ?
The solutions to the equation 24x^2+28x+4=0 are x=-1/6 ,x=-1
Find the zeros of 24x^2+28x+4=0
The zeros of 24x^2+28x+4=0 are x=-1/6 ,x=-1